class Solution:
def kthGrammar(self, N: int, K: int) -> int:
def solve(n, k):
if n==1 and k==1:
return False
mid = (2**(n-1))//2
if k <= mid:
return solve(n-1, k)
else:
return not solve(n-1, k-mid)
if solve(N, K):
return 1
else:
return 0
1516A - Tit for Tat | 622. Design Circular Queue |
814. Binary Tree Pruning | 791. Custom Sort String |
787. Cheapest Flights Within K Stops | 779. K-th Symbol in Grammar |
701. Insert into a Binary Search Tree | 429. N-ary Tree Level Order Traversal |
739. Daily Temperatures | 647. Palindromic Substrings |
583. Delete Operation for Two Strings | 518. Coin Change 2 |
516. Longest Palindromic Subsequence | 468. Validate IP Address |
450. Delete Node in a BST | 445. Add Two Numbers II |
442. Find All Duplicates in an Array | 437. Path Sum III |
436. Find Right Interval | 435. Non-overlapping Intervals |
406. Queue Reconstruction by Height | 380. Insert Delete GetRandom O(1) |
332. Reconstruct Itinerary | 368. Largest Divisible Subset |
377. Combination Sum IV | 322. Coin Change |
307. Range Sum Query - Mutable | 287. Find the Duplicate Number |
279. Perfect Squares | 275. H-Index II |